[Solution] [Manual] Richard G. Budynas and J. Keith Nisbett - Shigley`…
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[Solution] [Manual] Richard G. Budynas and J. Keith Nisbett - Shigley`s Mechanical Engineering Design - Intructor Solutions manual-McGraw-Hill ~ (2010)
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[Solution] [Manual] Richard G. Budynas and J. Keith Nisbett - Shigley`s Mechanical Engineering Design - Intructor Solutions manual-McGraw-Hill ~ (2010) , [Solution] [Manual] Richard G. Budynas and J. Keith Nisbett - Shigley`s Mechanical Engineering Design - Intructor Solutions manual-McGraw-Hill ~ (2010)기타솔루션 , 솔루션
癤 Chapter 1
Problems 1-1 through 1-6 are for student research. No standard solutions are provided.
1-7 From Fig. 1-2, cost of grinding to 0.0005 in is 270%. Cost of turning to 0.003 in is 60%.
Relative cost of grinding vs. turning = 270/60 = 4.5 times Ans. 1-8 CA = CB,
10 + 0.8 P = 60 + 0.8 P 0.005 P 2
P 2 = 50/0.005 P = 100 parts Ans.
1-9 Max. load = 1.10 P Min. area = (0.95)2A Min. strength = 0.85 S
To offset the absolute uncertainties, the design factor, from Eq. (1-1)
癤 Chapter 1
Problems 1-1 through 1-6 are for student research. No standard solutions are provided.
1-7 From Fig. 1-2, cost of grinding to 0.0005 in is 270%. Cost of turning to 0.003 in is 60%.
Relative cost of grinding vs. turning = 270/60 = 4.5 times Ans. 1-8 CA = CB,
10 + 0.8 P = 60 + 0.8 P 0.005 P 2
P 2 = 50/0.005 P = 100 parts …(투비컨티뉴드 )
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[Solution] [Manual] Richard G. Budynas and J. Keith Nisbett - Shigley`s Mechanical Engineering Design - Intructor Solutions manual-McGraw-Hill ~ (2010)
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