[Manual] William Hayt, John Buck - Engineering Electromagnetics - Full…
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Download : William Hayt John Buck Engineering Electromagnetics Full Solutions Manual (2011).pdf
Download : William Hayt John Buck Engineering Electromagnetics Full Solutions Manual (2011).pdf( 95 )
솔루션,전기전자,솔루션
癤 CHAPTER 1
1.1. Given the vectors M = 0ax + 4ay 8az and N = 8ax + 7ay 2az, 詮nd: a) a unit vector in the direction of M + 2N.
M + 2N = 10ax 4ay + 8az + 16ax + 14ay 4az = (26,10,4) Thus
(26,10,4)
a = |(26,10,4)| = (0.92,0.36,0.14)
b) the magnitude of 5ax + N 3M:
(5,0,0) + (8,7,) (0,12,4) = (43,,22), and |(43,,22)| = 48.6.
c) |M||2N|(M + N):
|(0,4,)||(16,14,)|(,11,0) = (13.4)(21.6)(,11,0) = (80.5,3193,902)
1.2. Vector A extends from the origin to (1,2,3) and vector B fr
癤 CHAPTER 1
1.1. Given the vectors M = 0ax + 4ay 8az and N = 8ax + 7ay 2az, 詮nd: a) a unit vector in the direction of M + 2N.
M + 2N = 10ax 4ay + 8az + 16ax + 14ay 4az = (26,10,4) Thus
(26,10,4)
a = |(26,10,4)| = (0.92,0.36,0.14)
b) the magnitude of 5ax + N 3M:
(5,0,0) + (8,7,) (0,12,4) = (43,,22), and |(43,,22)| = 48.6.
c) |…(투비컨티뉴드 )
[Manual] William Hayt, John Buck - Engineering Electromagnetics - Full Solutions Manual (2011)
[Manual] William Hayt, John Buck - Engineering Electromagnetics - Full Solutions Manual (2011)
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[Manual] William Hayt, John Buck - Engineering Electromagnetics - Full Solutions Manual (2011) , [Manual] William Hayt, John Buck - Engineering Electromagnetics - Full Solutions Manual (2011)전기전자솔루션 , 솔루션
솔루션/전기전자
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